#math trivia #259 solution

The side-by-side squares are of course 25 and 9. The problem doesn’t state exactly how much overlapping is allowed, so many forms are possible.  Presumably, every digit is involved in at least one of the two squares.  At least one digit must be involved in only one square, otherwise the solution is trivial (i.e., every square would overlap itself).

  • abc where these portions are squares
    • a and abc:  100, 121, 144, 169, 196
    • ab and abc:  169, 256, 361
    • ab and bc:  none
    • abc and b:  144, 196
    • abc and bc:  100
    • abc and c:  100, 121, 144, 169, 289, 324, 361
  • bc where these portions are squares:
    • b and bc:  16, 49
    • bc and c:  49, 64, 81

 

Leave a Reply

Fill in your details below or click an icon to log in:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out / Change )

Twitter picture

You are commenting using your Twitter account. Log Out / Change )

Facebook photo

You are commenting using your Facebook account. Log Out / Change )

Google+ photo

You are commenting using your Google+ account. Log Out / Change )

Connecting to %s