#math trivia #130 solution

#math trivia for #May9:  #130 can be expressed with two 1s and the rest (if any) all 0s in what bases?

Answer.  This is equivalent to asking for which bases b can 130 be expressed as

130 = b^x + b^y

for distinct x, y.  Without loss of generality, let y be the smaller of the two exponents.  Then b^y must divide into 130, which means that the possible values for b^y are 1, 2, 5, 10, 13, 26 and 65.

Now consider each value of b^y in turn:

  • 1:  y = 0 and b^x = 129, so b = 129, x = 1, y = 0.  130 is 11 base 129.
  • 2:  y = 1, b = 2, and b^x = 128, so x = 7.  130 is 10000010 base 2.
  • 5:  y = 1, b = 5, and b^x = 125, so x = 3.  130 is 1010 base 5.
  • 10:  y = 1, b = 10, and b^x = 120; no solution for x.
  • 13:  y = 1, b = 13, and b^x = 117; no solution for x
  • 26:  y = 1, b = 26, and b^x = 104; again no solution.
  • 65:  y = 1, b = 65, and b^x = 65; no solution because x would be the same as y.

There are therefore three bases that work:  129, 2 and 5.

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